Answer :
[tex] \bf ~~~~~~~~~~~~\textit{function transformations}
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f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
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f(x)= A\sqrt{ Bx+ C}+ D
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f(x)= A(\mathbb{R})^{ Bx+ C}+ D
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f(x)= A sin\left( B x+ C \right)+ D\\\\[-0.35em]
\rule{34em}{0.25pt} [/tex]
[tex] \bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
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\bullet \textit{ flips it sideways if } B\textit{ is negative} [/tex]
[tex] \bf ~~~~~~\textit{reflection over the y-axis}
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\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B} [/tex]
with that template above in mind, let's see,
[tex] \bf f(x)=\stackrel{A}{3}(\stackrel{B}{1}x\stackrel{C}{-9})+\stackrel{D}{0} [/tex]
A = 3, shrunk vertically by 1/3
B = 1, C = -9, C/B = -9, shifted horizontally 9 units to the right.
so f(x) = 3(x-9) is really f(x) = x, in disguise, shrunk and shifted horizontally.