Answer :

Riia

In this question it is given that the values of CD and CE are 20 and 32 respectively.

Since the length of CE is greater then of CD, so C and D could not be the end points.

Therefore, either D and E are the endpoints or C and E are the endpoints.

If D and E are the endpoints, then DE is the sum of 20 and 32 which is 52.

And if C and E are the endpoints, then DE is the difference of CE and CD that is 12.

So the possible values of DE are 12 and 52.

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