Answer :
Answer:
y = 12x + 9 is the answer.
Step-by-step explanation:
Since the given equation is 2x + 12 y = -1
12y = -2x -1
[tex]y=-\frac{1}{12}(2x+1)[/tex]
[tex]y=-\frac{1}{12}x-\frac{1}{12}[/tex]
Now this line is in the form of y = mx + c
Here m = slope = -1/12
We have to calculate the slope of another line perpendicular to this line and passing through (0, 9).
Let the equation is y = m' + c'
We know m×m' = -1 for two perpendicular lines
[tex]-(\frac{1}{12})(m')=-1[/tex]
m' = 12
Therefore the equation will be
y = 12x + c'
Since this line passes through ( 0, 9)
9 = 12×0 + c'
c' = 9
Now the equation will be
y = 12x + 9
This is the answer.
Answer:
y = 6x+9
Step-by-step explanation:
We have given an equation.
2x+12y=-1 eq(1)
y = mx+c is slope-intercept form of equation of line where m is slope and c is y intercept.
We can write eq(1) in slope-intercept form:
12y = -2x-1
y = 1/12(-2x-1)
y = -1/6x-1/12
let m₁ is slope of given line which is equal to -1/6.
Perpendicular lines have slopes negative reciprocals of each other.
Let m₂ is slope of perpendicular line.
m₂ = 6 and we have given y-intercept = 9.
Putting the value of c and m₂ in slope-intercept form of equation, we have
y = 6x+9 is slope-intercept of line that is perpendicular to the given line and passes through the point (0,9).