Answer :

tramserran

Answer:  126°

Step-by-step explanation:

[tex]\text{Equation 1:}\ \stackrel\frown{CYE}+\stackrel\frown{CE}=360^o\quad \rightarrow \quad \stackrel\frown{CYE}\ =360\ -\stackrel\frown{CE}\\\\\text{Equation 2:}\ \dfrac{\stackrel\frown{CYE}-\stackrel\frown{CE}}{2}=52^o\quad \rightarrow \quad \stackrel\frown{CYE}-\stackrel\frown{CE}=104\\\\\text{Use substitution method to solve for}\stackrel\frown{CE}:\\\\(360 - \stackrel\frown{CE})-\stackrel\frown{CE}=104\\\\360-2\stackrel\frown{CE}=104\\\\-2\stackrel\frown{CE}=-254\\\\\stackrel\frown{CE}=126[/tex]

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