Answer :
Answer:
[tex]12\ nickel[/tex]
[tex]10\ quarter[/tex]
Step-by-step explanation:
we know that
[tex]1\ nickel=\$0.05[/tex]
[tex]1\ quarter=\$0.25[/tex]
Let
x------> the number of nickel coins
y-----> the number of quarter coins
we know that
[tex]x+y=22[/tex]
[tex]x=22-y[/tex] -----> equation A
[tex]0.05x+0.25y=3.10[/tex] ----> multiply by 100 both sides
[tex]5x+25y=310[/tex] -----> equation B
Substitute equation A in equation B and solve for y
[tex]5(22-y)+25y=310[/tex]
[tex]110y-5y+25y=310[/tex]
[tex]20y=310-110[/tex]
[tex]20y=200[/tex]
[tex]y=10\ quarter[/tex]
[tex]x=22-y[/tex] ------> [tex]x=22-10=12\ nickel[/tex]