Answer :
Solutions
A sphere has a radius of 7.5 ft. To find the volume we need to use this equation ≥ v=4/3πr³.
π = ( 3. 14)
r = 7.5
Calculations
v=4/3πr³
v=4/3π ( 7.5 x 7.5 x 7.5 )
v=4/3π (421)
v=4/3 (3.14) (421)
v=4/3 (1321)
v=1.3 (1321)
v = 1717.3.
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Solutions
A storage tank holds 235,500 in³ of a chemical. The chemical is dispensed to completely fill 25 identical cylindrical containers, each with a radius of 5 inches.
To solve this problem we have to use this equation - V = πr²h. We know the radius is 5 and the volume is 235,500³.
Calculations
V = πr²h
235,500³ = (3.14)(5)²)h
235,500³ = (3.14) (25))h
235,500³ = 78.5
[tex] \frac{235,500}{78.5} [/tex] [tex] \frac{78.5}{78.5} [/tex]
235,500 ÷ 78.5 = h
h = 3000
A sphere has a radius of 7.5 ft. To find the volume we need to use this equation ≥ v=4/3πr³.
π = ( 3. 14)
r = 7.5
Calculations
v=4/3πr³
v=4/3π ( 7.5 x 7.5 x 7.5 )
v=4/3π (421)
v=4/3 (3.14) (421)
v=4/3 (1321)
v=1.3 (1321)
v = 1717.3.
≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡
Solutions
A storage tank holds 235,500 in³ of a chemical. The chemical is dispensed to completely fill 25 identical cylindrical containers, each with a radius of 5 inches.
To solve this problem we have to use this equation - V = πr²h. We know the radius is 5 and the volume is 235,500³.
Calculations
V = πr²h
235,500³ = (3.14)(5)²)h
235,500³ = (3.14) (25))h
235,500³ = 78.5
[tex] \frac{235,500}{78.5} [/tex] [tex] \frac{78.5}{78.5} [/tex]
235,500 ÷ 78.5 = h
h = 3000