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write an equation in slope intercept form for the line that passes through (4, -4) and is parallel to 3x+4x=2y-9

Answer :

gmany

Answer:

[tex]\large\boxed{y=\dfrac{7}{2}x-18}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

Convert the equation of a line 3x + 4x = 2y - 9 to the slope-intercept form:

[tex]3x+4x=2y-9[/tex]

[tex]7x=2y-9[/tex]             add 9 to both sides

[tex]7x+9=2y[/tex]       divide both sides by 2

[tex]\dfrac{7}{2}x+\dfrac{9}{2}=y\to y=\dfrac{7}{2}x+\dfrac{9}{2}[/tex]

Parallel lines have the same slope. Therefore we have the equation:

[tex]y=\dfrac{7}{2}x+b[/tex]

Put the coordinates of the point (4, -4) to the equation:

[tex]-4=\dfrac{7}{2}(4)+b[/tex]

[tex]-4=7(2)+b[/tex]

[tex]-4=14+b[/tex]       subtract 14 from both sides

[tex]-18=b\to b=-18[/tex]

Finally we have the equation:

[tex]y=\dfrac{7}{2}x-18[/tex]

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