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Write a sine function with the given amplitude, period, phase shift, and vertical shift.


amplitude: 2; period: pi; phase shift: -1/8 pi; vertical shift: 3

Answer :

alinakincsem

Answer:

[tex]y = 2 sin (\frac{2x- 1}{16 \pi} ) - 1[/tex]

Step-by-step explanation:

We know that the standard form of equation for the sine function is given by:

[tex]y = Asin(Bx-C)[/tex] where [tex]A[/tex] is amplitude, period is [tex]\frac{2\pi }{B}[/tex] and the phase shift is equal to [tex]Bx-C[/tex] set to zero. [tex]C[/tex] is then obtained by this equation.

Here in this problem: A is equal to 2, period=2π/B=2π/2=π, where B is equal to 2 and the phase shift is equal to 2x - 1/16 pi = 0.

[tex] y = 2 sin (\frac { 2 x - 1 } { 16 \pi} ) - 1[/tex]

Answer: f(x)= +-2sin(2t+1/4pi)+3

Step-by-step explanation:

Did it on edge 21

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