Answer :

carlosego

Answer:

Last option

[tex]d>3[/tex] or [tex]d<-3[/tex]

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function [tex]f(x) = |x|[/tex]  x> 0 for all real numbers.

Then the inequation:

[tex]|d|> 3[/tex] has two cases

[tex](d)[/tex]    if [tex]d>0[/tex]  (i)

[tex]-(d)[/tex]    if [tex]d< 0[/tex] (ii)

We solve the case (i)

[tex]d> 3[/tex]

We solve the case (ii)

[tex]-d>3\\d < -3[/tex]

Then the solution is:

[tex]d>3[/tex] or [tex]d<-3[/tex]

lublana

Answer:

Last choice is the correct graph.

Step-by-step explanation:

We have been given inequality [tex]|d|>3[/tex]. Now we need to find out which of the given number lines shows the correct solution set for [tex]|d|>3[/tex].

We know that [tex]|x|>a[/tex] can be broken into :

[tex]x>+a[/tex] or [tex]x<-a[/tex]

Same way we can break [tex]|d|>3[/tex] into two parts as:

[tex]d>+3[/tex] or [tex]d<-3[/tex]

Since it has only < symbol but not equal so we make an open circle at both +3 and -3.

Hence last choice is the correct graph.

${teks-lihat-gambar} lublana

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