Answer :
Answer: [tex]\bold{a_1=9\qquad a_2=38\qquad a_3=183\qquad a_4=908}[/tex]
Step-by-step explanation:
[tex]a_1=9\qquad a_n=5(a_{n-1})-7\\\\a_2=5(a_1)-7\\.\quad =5(9)-7\\.\quad =45-7\\.\quad =\large\boxed{38}\\\\\\a_3=5(a_2)-7\\.\quad =5(38)-7\\.\quad =190-7\\.\quad =\large\boxed{183}\\\\\\a_4=5(a_3)-7\\.\quad =5(183)-7\\.\quad =915-7\\.\quad =\large\boxed{908}[/tex]
Answer:
[tex]\large\boxed{a_1=9,\ a_2=38,\ a_3=183,\ a_4=908}[/tex]
Step-by-step explanation:
We have the sequence in recursive formula:
[tex]\left\{\begin{array}{ccc}a_1=99\\a_n=5(a_{n-1})-7\end{array}\right[/tex]
Therefore
[tex]a_2=5a_{2-1}-7=5a_1-7\to a_2=5(9)-7=45-7=38\\\\a_3=5a_{3-1}-7=5a_2-7\to a_3=5(38)-7=190-7=183\\\\a_4=5a_{4-1}-7=5a_3-7\to a_4=5(183)-7=915-7=908[/tex]
