When x is 2, y is 4, p is 0.5, and m is 2. If x varies directly with the product of p and m and inversely with y, which equation models the situation?
xpmy=8
xy/pm=8
xpm/y=0.5
x/pmy=0.5

Answer :

The correct answer for the question that is being presented above is this one: "xy / pm = 8." The equation that models the situation is this xy / pm = 8


If x varies directly with the product of p and m and inversely with y:
x = pm/y
2 = 0.5*2 / 4
8 = 1

Then,
xy / pm = 8

Answer:

The equation models the situation.

[tex]\frac{xy}{mp} = 8[/tex]

Step-by-step explanation:

As given

If x varies directly with the product of p and m and inversely with y.

Thus

[tex]x\propto \frac{mp}{y}[/tex]

[tex]x=k \frac{mp}{y}[/tex]

Where k is the constant of proportionality .

Simplify the above

[tex]\frac{xy}{mp} = k[/tex]

As given

When x is 2, y is 4, p is 0.5, and m is 2.

Putting the value in the above

[tex]\frac{2\times 4}{0.5\times 2} = k[/tex]

[tex]\frac{8}{1.0} = k[/tex]

k = 8

Therefore

[tex]\frac{xy}{mp} = 8[/tex]

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