Answered

The ratio of Aziz's money to Osman's money was 2:1 at first. After Aziz spent $10 ratio became 4:3. How much money did each boy have at first

Answer :

calculista

Answer:

Aziz's money was $30

Osman's  money was $15

Step-by-step explanation:

Let

x-----> Aziz's money at first

y-----> Osman's  money

we know that

[tex]\frac{x}{y}=\frac{2}{1}[/tex]

[tex]x=2y[/tex] ------> equation A

[tex]\frac{x-10}{y}=\frac{4}{3}[/tex] -----> equation B

substitute equation A in equation B and solve for y

[tex]\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15[/tex]

Find the value of x

[tex]x=2(15)=30[/tex]

therefore

At first

Aziz's money was $30

Osman's  money was $15

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