Answer :
Answer: last option
Step-by-step explanation:
The formula to find the Discriminant is:
[tex]D=b^2-4ac[/tex]
Given the quadratic equation [tex]n^2-n-6=0[/tex], you can identify that:
[tex]a=1\\b=-1\\c=-6[/tex]
Now, you can substitute values into the formula [tex]D=b^2-4ac[/tex], then:
[tex]D=b^2-4ac\\D=(1)^2-4(1)(-6)\\D=25[/tex]
As the Discriminant is greater than 0 ([tex]D>0[/tex]), then the quadratic equation [tex]n^2-n-6=0[/tex] has two distinct real solutions.
ANSWER
2
EXPLANATION
The given quadratic equation is
[tex] {n}^{2} - n - 6 = 0[/tex]
Comparing to
[tex]a{n}^{2} + b n + c = 0[/tex]
We have a=1, b=-1 and c=-6
The discriminant is given by the formula,
[tex]D = {b}^{2} - 4ac[/tex]
Plug in the values to get,
[tex]D = {( - 1)}^{2} - 4(1)( - 6)[/tex]
[tex]D =1 + 24 = 25[/tex]
Since the discriminant is positive, the equation has two real roots.