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A force of 100 newtons will stretch a spring 0.25 meters. How far will a force of 80 newtons stretch it?

Use Hooke's law F = kx.

A.
0.04 meters

B.
0.2 meters

C.
0.4 meters

D.
2 meters

Answer :

I set up an equal proportion [tex]\frac{100}{0.25} = \frac{80}{x}[/tex]

cross multiply to get 80 * 0.25 = 100x

20 = 100x; divide both sides by 100

0.2 = x so the answer is choice B

Answer:

B. 0.2 meters.

Step-by-step explanation:

Let x represent meters of spring stretched by 80 newtons.

We have been given that a force of 100 newtons will stretch a spring 0.25 meters.

We will use Hooke's law, which states that the force needed to compress or extend a spring is directly proportional to the distance we stretch it.[tex]N=kx[/tex], where,

N = Force in Newtons,

k = The spring constant,

x = Amount of extension in meters.

Let us find spring constant by substituting [tex]N=100[/tex] and [tex]x=0.25[/tex].

[tex]100=k*0.25[/tex]

[tex]\frac{100}{0.25}=\frac{k*0.25}{0.25}[/tex]

[tex]400=k[/tex]

So, our equation would be [tex]N=400x[/tex].

Now, we will substitute [tex]N=80[/tex] in our equation to find x.

[tex]80=400x[/tex]

Upon dividing both sides of our equation by 400 we will get,

[tex]\frac{80}{400}=\frac{400x}{400}[/tex]

[tex]\frac{1}{5}=x[/tex]

[tex]0.2=x[/tex]

Therefore, the force of 80 newtons will stretch the spring 0.2 meters and option B is the correct choice.

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