In rhombus JKLM, if m<KLJ = 38°, find m<JIVIL.

Answer:
∠JML = 104°
Step-by-step explanation:
JL bisects angle KLM, so ...
∠KLM = 2·∠KLJ = 2·38° = 76°
Adjacent angles in any parallelogram are supplementary, so ...
∠JML = 180° -∠KLM = 180° -76°
∠JML = 104°