Answer :
Answer:
a.) 22.4 L Ne.
Explanation:
It is known that every 1.0 mol of any gas occupies 22.4 L.
For the options:
- 22.4 L Ne:
It represents 1.0 mol of Ne.
- 20 L Ar:
using cross multiplication:
1.0 mol occupies → 22.4 L.
??? mol occupies → 20 L.
The no. of moles of (20 L) Ar = (1.0 mol)(20 L)/(22.4 L) = 0.8929 mol.
- 2.24 L Xe:
using cross multiplication:
1.0 mol occupies → 22.4 L.
??? mol occupies → 2.24 L.
The no. of moles of (2.24 L) Xe = (1.0 mol)(2.24 L)/(22.4 L) = 0.1 mol.
- So, the gas that has the largest number of moles at STP is: a.) 22.4 L Ne.