Answer :

MathPhys

Answer:

an = 6 (1/4)^(n-1)

Step-by-step explanation:

We're given the first term, a₁ = 6.

The common ratio is a term aₓ divided by the previous term aₓ₋₁.

aₓ = 1/4 aₓ₋₁

aₓ / aₓ₋₁ = 1/4

r = 1/4

Therefore:

an = 6 (1/4)^(n-1)

Your answer is correct, good job!

The recursive rule for a geometric sequence is given a₁ = 6, aₓ = 1/4 aₓ₋₁. The explicit rule would be [tex]a_n = 6 (1/4)^{n-1}[/tex].

What is a geometric sequence and how to find its nth terms?

Suppose the initial term of a geometric sequence is a

and the term by which we multiply the previous term to get the next term is r

Then the sequence would look like

[tex]a, ar, ar^2, ar^3, \cdots[/tex]

Thus, the nth term of such sequence would be  

[tex]T_n = ar^{n-1}[/tex]

We have been given the first term,

a₁ = 6.

The common ratio is the term aₓ divided by the previous term aₓ₋₁.

aₓ = 1/4 aₓ₋₁

aₓ / aₓ₋₁ = 1/4

r = 1/4

Therefore:

[tex]a_n = 6 (1/4)^{n-1}[/tex]

Hence, The explicit rule would be [tex]a_n = 6 (1/4)^{n-1}[/tex].

Learn more about geometric sequence here:

https://brainly.com/question/2735005

#SPJ2

Other Questions