Answer :
Answer:
Height of the painting is 30 inches.
Step-by-step explanation:
If the rectangular frame of a painting is in the shape of ABCD.
Measure of frame's diagonal AC is 50 inches and it forms an angle of 36.87° angle with the bottom of the frame BC.
Now we have to determine the height of the painting.
Sin(36.87)° = [tex]\frac{AB}{AC}[/tex]
0.60 = [tex]\frac{x}{50}[/tex]
x = 50×0.6
x = 30 inches
Therefore, height of the painting is 30 inches.
