Answer:
The system of equations is
[tex]x-2y=10[/tex]
[tex]x-3y=-18[/tex]
Step-by-step explanation:
we have
[tex]\frac{1}{2}x-5=\frac{1}{3}x+6[/tex]
Let set both sides of the equation separately equal to y
so
Left side
[tex]y=\frac{1}{2}x-5[/tex]
Multiply both sides by 2 to remove the fraction
[tex]2y=x-10[/tex]
Rewrite as standard equation
[tex]x-2y=10[/tex] -----> equation A
Right side
[tex]y=\frac{1}{3}x+6[/tex]
Multiply both sides by 3 to remove the fraction
[tex]3y=x+18[/tex]
Rewrite as standard equation
[tex]x-3y=-18[/tex] -----> equation B
therefore
The system of equations is
[tex]x-2y=10[/tex]
[tex]x-3y=-18[/tex]
