A pizza restaurant sold 24 cheese pizzas and 16 pizzas with one or more toppings. Twelve of the cheese pizzas were eaten, and 10 of the pizzas with one or more toppings were eaten at work. If a pizza was selected at random, find the probability of each:a. It was a cheese pizza eaten at work.b. It was a pizza with either one or more toppings, and it was not eaten at work.c. It was a cheese pizza, or it was a pizza eaten at work.

Answer :

Answer:

Step-by-step explanation:

                                cheese  With toppings    Total

No of pizzas sold    24                     16                40

Eaten at work           12                     10                22

Not eaten at work     12                      6                18

a) Prob for a cheese pizza eaten at work=[tex]\frac{12}{40} =0.30[/tex]

b) Prob a pizza with either one or more toppings, and it was not eaten at work.=[tex]\frac{6}{40} =0.15[/tex]

c) Prob for a cheese pizza, or it was a pizza eaten at work.=P(cheese)+P(pizza eaten at work)-P(both)

= [tex]\frac{24}{40} +\frac{22}{40} -\frac{12}{40} \\=\frac{34}{40} \\=0.85[/tex]

The probability of cheese pizza eaten, pizza with either one or more toppings and it was not eaten, and cheese pizza or it was a pizza eaten are 0.30, 0.15, and 0.85 respectively.

What is probability?

Probability means possibility. It deals with the occurrence of a random event. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

According to the condition, the table is shown.

                                         Cheese           With toppings          Total

No. of pizza sold                  24                        16                       40

Eaten at work                       12                         10                       22

Not eaten at work                12                         6                         18

a.  Probability for cheese pizza eaten at work will be

[tex]\rm Probability = \dfrac{12}{40} = 0.30[/tex]

b.  Probability of a pizza with either one or more toppings and it was not eaten at work will be

[tex]\rm Probability = \dfrac{6}{40} = 0.15[/tex]

c.  Probability for a cheese pizza or it was a pizza eaten at work will be

[tex]\rm Probability = P(cheese) + P(eaten \ at \ work) - P ( both) \\\\\rm Probability = \dfrac{24}{40} + \dfrac{22}{40} - \dfrac{12}{40}\\\\\rm Probability = 0.85[/tex]

More about the probability link is given below.

https://brainly.com/question/795909

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