Answer :
Answer:
Net discharge per hour will be 3.5325 [tex]m^3/hr[/tex]
Explanation:
We have given internal diameter d = 25 mm
Time = 1 hour = 3600 sec
So radius [tex]r=\frac{d}{2}=\frac{25}{2}=12.5mm=12.5\times 10^{-3}m[/tex]
We know that area is given by
[tex]A=\pi r^2=3.14\times (12.5\times 10^{-3})^2=490.625\times 10^{-6}m^2[/tex]
We know that discharge is given by [tex]Q=AV[/tex], here A is area and V is velocity
So [tex]Q=AV=490.625\times 10^{-6}\times 2=981.25\times 10^{-6}m^3/sec[/tex]
So net discharge in 1 hour = [tex]981.25\times 10^{-6}m^3/sec\times 3600=3.5325m^3/hour[/tex]