Answer :
[tex]\bf 3x + 4y - 12 = 0\implies 4y-12 = -3x\implies 4y=-3x+12 \\\\\\ y = \cfrac{-3x+12}{4}\implies y = \cfrac{-3x}{4}+\cfrac{12}{4} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{4}}x\stackrel{\stackrel{b}{\downarrow }}{+3} \qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
Answer:
The slope of the equation is: [tex]\frac{-3}{4}[/tex]
The y intercept is: 3 or (0,3)
Step-by-step explanation:
Consider the provide equation of line.
[tex]3x+4y-12=0[/tex]
The slope intercept form is: [tex]y=mx+c[/tex]
Where m is the slope and c is the y intercept.
Now convert the provided equation into slope intercept form as shown.
[tex]4y=12-3x[/tex]
[tex]y=\frac{-3}{4}x+3[/tex]
Now compare the above equation with slope intercept form.
By the comparison we can concluded that
The slope of the equation is: [tex]\frac{-3}{4}[/tex]
The y intercept is: 3 or (0,3)