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Two cars simultaneously left Points A and B and headed towards each other, and met after 3 hours and 15 minutes. The distance between points A and B is 364 miles. What is the speeds of the cars, if one of the cars travels 12 mph faster than the other?

Answer :

hamzazafer04

Answer:

50 62

Step-by-step explanation:

Answer:

48.5 and 60.5 mph

Step-by-step explanation:

Given distance between A and B is 364 miles

Let they meet after y and 364 - y miles.

And, Let speed of one car is x then speed of other car will be (x + 12) mph

Also time after they meet is 3 hours and 15 minutes = 13 ÷ 4 hours.

Using the distance- time formula,

We get equation:

[tex]\frac{13}{4}=\frac{364-y}{x+15} \\and, \frac{13}{4}=\frac{y}{x}[/tex]

Thus, After simplifying we get,

13x + 4y = 1261

and, 13x - 4y = 0

Solving we get the value of x = 48.5

Thus, the Speed is 48.5 and 60.5 mph

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