Answer :
Answer:
Uncorrected values for
For circuit P
R = 2.4 ohm
For circuit Q
R = 2.4 ohm
Corrected values
for circuit P
R = 12 OHM
For circuit Q
R = 2.3 ohm
Explanation:
Given data:
Ammeter resistance 0.10 ohms
Resister resistance 3.0 ohms
Voltmeter read 6 volts
ammeter reads 2.5 amp
UNCORRECTED VALUES FOR
1) circuit P
we know that IR =V
[tex]R = \frac{6}{2.5} - 2.4 ohm[/tex]
2) circuit Q
R = 2.4 ohm as no potential drop across ammeter
CORRECTED VALUES FOR
1) circuit p
IR = V
[tex]\frac{3R}{R+3} \times 2.5 = 6[/tex]
R= 12 ohm
2) circuit Q
[tex]I\times (R+0.1) =V[/tex]
[tex]R+0.1 =\frac{6}{2.5}[/tex]
R = 2.3 ohm
