Answer :
Answer:
Speed, v = 13.39 m/s
Explanation:
It is given that,
The coefficient of static friction between the road and the tires on a car is 0.60, [tex]\mu_s=0.6[/tex]
Radius of the curve, r = 30.5 m
When the car is at the verge of sliding,
[tex]\dfrac{mv^2}{r}=\mu_s\ mg[/tex]
v is the speed of the car
[tex]v=\sqrt{\mu_s\ gr}[/tex]
[tex]v=\sqrt{0.6\times 9.8\times 30.5}[/tex]
v = 13.39 m/s
So, the speed the car on the verge of sliding is 13.39 m/s. Hence, this is the required solution.