Endpoints of segment MN have coordinates (0, −3), (−2, −4). Endpoints of segment AB have coordinates (2, 5), (4, k).


What value of k makes these segments perpendicular?

Answer :

Answer:

The answer to your question is: k = 1

Step-by-step explanation:

Data

MN    (0, -3)  ,  (-2, -4)

AB     (2, 5)   ,  (4 , k)

Formula

 [tex]m = \frac{y2 - y1}{x2 - x1}[/tex]

Process

Slope MN = [tex]\frac{-4 + 3}{-2 + 0}[/tex]   = [tex]\frac{1}{2}[/tex]

Slope AB = [tex]\frac{k - 5}{4 - 2}  = \frac{k - 5}{2}[/tex]

If the lines are perpendicular then,

                  [tex]- 2 = \frac{k - 5}{2}[/tex]

                  -4 = k - 5

                 k = -4 + 5

                 k = 1

The value of k is 1 which makes these segments perpendicular.

What is coordinate geometry?

A coordinate plane is a 2D plane that is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The given coordinates are:-

MN    (0, -3)  ,  (-2, -4)

AB     (2, 5)   ,  (4 , k)

The formula for the slope is calculated as:-

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Calculate the slope MN and AB as below:-

Slope MN = ( -4 + 3 ) / ( -2 + 0) = 1 / 2  

Slope AB = ( k - 5 ) / 2

If the lines are perpendicular then,

-2 = ( k - 5 ) / 2

-4 = k - 5

k = -4 + 5

k = 1

Therefore, the value of k is 1 which makes these segments perpendicular.

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