Answer :
If you would like to find the x-intercepts of the function f(x) = - 2 * x^2 - 3 * x + 20, you can calculate this using the following steps:
f(x) = - 2 * x^2 - 3 * x + 20
f(x) = - (2x - 5) * (x + 4)
1. x = - 4
2. x = 5/2
(x, y) = (-4, 0)
The correct result would be (-4, 0).
f(x) = - 2 * x^2 - 3 * x + 20
f(x) = - (2x - 5) * (x + 4)
1. x = - 4
2. x = 5/2
(x, y) = (-4, 0)
The correct result would be (-4, 0).
The x-intercepts of the given function are (2.5, 0) and (-4, 0)
Solving quadratic equations
From the question, we are to determine the x-intercepts of the given function
The given function is
f(x) = –2x² – 3x + 20
To determine the x-intercepts of the function, we will determine its zeros
That is, we would solve
0 = –2x² – 3x + 20
This can be rewritten as
2x² + 3x - 20 = 0
Solve by factoring
2x² + 8x - 5x - 20 = 0
2x(x + 4) -5(x + 4) = 0
Then,
(2x - 5)(x +4) = 0
2x - 5 = 0 OR x +4 = 0
2x = 5 OR x = -4
x = 5/2 OR x = -4
x = 2.5 OR x = -4
Hence, the x-intercepts of the function are (2.5, 0) and (-4, 0)
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