The surface area of the square pyramid is 9.25 square feet.
"A three-dimensional geometric shape that has a square base and four triangular sides that are joined at a vertex."
"It is the sum of all the surfaces of the pyramid."
For given question,
We have been given a square pyramid.
The sides of the square base are labeled 0.5 foot.
So, the area of the square base would be,
[tex]\Rightarrow A_1=(0.5)^2\\\\\Rightarrow A_1=0.25[/tex]
The height of one of the triangular sides is labeled 9 feet.
And the base of the triangular side is the side of square.
So, the length of the triangular base is 0.5 ft.
So, the area of the four triangular bases would be,
[tex]\Rightarrow A_2=4\times (\frac{1}{2}\times 9\times 0.5 )\\\\\Rightarrow A_2=4\times 2.25\\\\\Rightarrow A_2=9[/tex]
The surface area of the square pyramid is the sum of the square base and four triangular bases.
So, the surface area of the square pyramid would be,
[tex]A=A_1+A_2\\\\A=0.25+9\\\\A=9.25[/tex]square feet
Therefore, the surface area of the square pyramid is 9.25 square feet.
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