chodeking
Answered

Which value must be added to the expression x^2 +16x to make it perfect-square trinomial?

A-8

B-32

C-64

D-256

Edit: it’s not A

Answer :

helpmewiththings49
x^2 + 16x + ?
a^2 + 2ab + b
(a + b)^2 which is a perfect square.

To find b to determine the last value, you divide 16x by 2x.
so:
b = 8
the last value would be 8^2 which is 64.

Hence answer is C - 64
facundo3141592

A perfect-square trinomial comes from the expansion:

(a + b) = a^2 + 2*a*b + b^2

Using that, we will get that the correct option is C, we need to add 64.

Let's see how to get the correct option.

We start with x^2 + 16*x + K

Where K is the value that we must find. Let's rewrite our expression like the perfect-square trinomial:

x^2 + 2*8*x + K

Then, comparing with the general form, we have a = x, b = 8, thus this will only be a perfect-square trinomial if K = 8^2 = 64

The perfect-square trinomial will be x^2 + 16*x + 64

So the correct option is C.

If you want to learn more, you can read:

https://brainly.com/question/15092485

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