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If a displacement of a body at an instant is given by:
X=22 + At + B√t
Where X is measured in meters and t is measured in seconds
Find the dimensions of A and B
Plz answer with explanation

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Answer :

Answer:

A = m / sec    B= 1/2 x m x sec^ -.5

Explanation:

X= 22 + At + B x t^1/2 is an equation for rectilinear motion similar to:

x= x0 + vx0 . t + 1/2 ax . t^2

therefore vx = A or velocity  m/sec , B= is the acceleration

B =( 1/2 m/sec^2 . sec^2) / sec^1/2

B= 1/2 x m x sec^ --1/2

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