Nina invests a sum of money in a savings account with an
annual interest rate of 4.61% compounded continuously.
After 6 years, the balance reaches $5274.56. What
was the amount of the initial investment?

And I would like the formula to use please :)

Answer :

Answer:

The amount of the initial investment by Nina is $2271 approximately.

Solution:

Given, Nina invests a sum of money in a savings account with an annual interest rate of 4.61% compounded continuously.  

After 6 years, the balance reaches $5274.56.  

We have to find what was the amount of the initial investment?

We know that, compound interest is given as

[tex]\text { Compound interest }=\text { amount } \times\left(1+\frac{\text { interest rate }}{100}\right)^{\text {time period }}[/tex]

Now, balance = invested amount + compound interest.

[tex]\begin{array}{l}{5274.56=\text { amount }+\text { amount } \times\left(1+\frac{4.61}{100}\right)^{6}} \\\\ {5274.56=\text { amount }\left(1+\left(1+\frac{4.61}{100}\right)^{6}\right)} \\\\ {5274.56=\text { amount }\left(1+(1+0.0461)^{6}\right)} \\\\ {5274.56=\text { amount } \times \left(1+1.0461^{6}\right)} \\\\ {5274.56=\text { amount } \times (1+1.31050)} \\\\ {\text { Amount }=\frac{5274.56}{2.31050}=2271.1729}\end{array}[/tex]

Hence, the invested amount of money is $2271 approximately.

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