Answered

How fast must a 1.88-9 ping-pong ball move (in m/s) in order to have the same kinetic energy as a 230.5 g baseball moving
58.5 m/s?

Answer :

MathPhys

Explanation:

KE = KE

½ mv² = ½ mv²

½ (1.88 g) v² = ½ (230.5 g) (58.5 m/s)²

v = 648 m/s

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