Answer :
Answer:
22.91 m/s
Explanation:
Data provided in the question:
Horizontal acceleration, a = 15 m/s²
Distance from start to cliff = 70 m
now,
Time taken to reach 70 m
from Newton's equation of motion, we have
[tex]s=ut+\frac{1}{2}at^2[/tex]
here,
s is the distance
a is the acceleration
t is the time
on substituting the respective values, we get
[tex]70=0\times t+\frac{1}{2}\times15\times t^2[/tex]
or
t² = 9.333
or
t = 3.05 s
therefore , the minimum speed = [tex]\frac{\textup{Distance}}{\textup{Time}}[/tex]
= [tex]\frac{\textup{70}}{\textup{3.05}}[/tex]
= 22.91 m/s