Answer :
Answer:
(A) Acceleration will be [tex]240.3846\times 10^{12}m/sec^2[/tex]
(b) Time taken will be [tex]1.4\times 10^{-8}sec[/tex]
(c) Force will be [tex]2189.9\times 10^{-19}N[/tex]
Explanation:
We have given that electron starts from rest so initial velocity u = 0 m/sec
Final velocity [tex]v=2.50\times 10^6m/sec[/tex]
Mass of electron [tex]m=9.11\times 10^{-31}kg[/tex]
Distance traveled by electron [tex]s=1.30cm =0.013m[/tex]
From third equation of motion we know that [tex]v^2=u^2+2as[/tex]
(a) So [tex](2.5\times 10^6)^2=0^2+2\times a\times 0.013[/tex]
[tex]a=240.3846\times 10^{12}m/sec^2[/tex]
(b) From first equation of motion we know that v = u+at
So [tex]2.50\times 10^6=0+240.3846\times 10^{12}t[/tex]
[tex]t=0.014\times 10^{-6}=1.4\times 10^{-8}sec[/tex]
(c) From newton's law we know that force
[tex]F=ma=9.11\times 10^{-31}\times 240.3846\times 10^{12}=2189.9\times 10^{-19}N[/tex]