Answer :
Answer:
X and Y are stochastically dependent RVs .
Step-by-step explanation:
Let ,
X = sum of the values that come up after throwing n (≥ 1) fare dice.
Y = number of times an odd number come up.
Let, n = 3
then, P(X =6) = p (say) clearly 0 < p < 1
and P (Y = 3) = [tex]\frac{1}{8}[/tex]
And,
P( X = 6, Y = 3) = 0 ≠ [tex]P(X = 6) \times P(Y= 3)[/tex]
Hence, X and Y are stochastically dependent RVs