Answer :
-- When he's at rest, his kinetic energy is zero.
-- When he reaches 6.5 m/s, his kinetic energy is . . .
KE = (1/2) (m) (v²)
KE = (34 kg) (42.25 m²/s²)
KE = 1,436.5 Joules
That's the amount of energy that has to come from somewhere, in order to boost him to that speed.
The Kinetic energy will be "1436.5 Joules".
Given values are:
Mass,
- m = 68 kg
Speed,
- v = m/s
As we know the formula,
→ [tex]Kinetic \ energy = \frac{1}{2}mv^2[/tex]
By substituting the given values, we get
→ [tex]= \frac{1}{2} (68)(6.5)^2[/tex]
→ [tex]= \frac{1}{2}\times 68\times 42.25[/tex]
→ [tex]= 34\times 42.25[/tex]
→ [tex]= 1436.5 \ Joules[/tex]
Thus the above answer is appropriate.
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