Answer :
We will define the Total mass to calculate the force, so our values are:[tex]M_p = 69*27=1823Kg\\M_g=15*3=45Kg\\M_c=3*5=15Kg\\M_B=25Kg[/tex]
Total Mass [tex]= 1863+45+15+25=1948Kg[/tex]
The Weight is,
[tex]F=mg=1948*98=19090.4N[/tex]
Through the hook's Law we calculate X.
[tex]F_s=Kx[/tex], where x is the lenght of compression and K the Spring constant.
We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)
[tex]X = \frac{F_s}{x} \\X = \frac{1909.4}{k}[/tex]
I assume a value of [tex]K=4*10^4N/m[/tex]
[tex]X= \frac{1909.4}{4*10^4} = 0.48m[/tex]
The compression of the spring at the given weight is 79.5 cm.
"Your question is not complete, it seems to be missing the following information below";
the spring constant of the taptap is k =2.4 × 10⁴ N/m
The given parameters;
- mass of each of the 27 persons, = 69 kg
- mass of each of the 3 goats, = 15 kg
- mass of each of the 5 chickens, = 3 kg
- mass of the bananas, = 25 kg
The total mass of all the passengers contained in the taptap is calculated as;
- total mass of the persons = 27 x 69 = 1863 kg
- total mass of the goats = 3 x 15 = 45 kg
- total mass of the chickens = 5 x 3 = 15 kg
- total mass of the bananas = 25 kg
The total mass = (1863 + 45 + 15 + 25)kg
The total mass = 1948 kg
The extension of the spring is calculated as follows;
[tex]F = kx\\\\x = \frac{F}{k} = \frac{mg}{k} \\\\x = \frac{(1948\times 9.8)}{2.4\ \times \ 10^4} \\\\x = 0.795 \ m\\\\x = 79.5 \ cm[/tex]
Thus, the compression of the spring at the given weight is 79.5 cm.
Learn more here:https://brainly.com/question/21321449