James was going to have 6 young people play a Bible game that uses 4 players around a table. The position at the table is important. He did not realize how many arrangements of players there would be. If it took 30 minutes to play one setting , how long would it take in hours for all of the position arrangements of players to compete?

Answer :

Answer:

12 hours

Step-by-step explanation:

6x4=24

24/2=12

First of all, we have to decide the four players out the 6 young people. By definition, the number of subsets of 4 elements from a set of 6 elements is

[tex]\displaystyle \binom{6}{4}[/tex]

Since the order is important, we have to add the fact that each of these subsets can be ordered in 4! ways, leading to a total of

[tex]\displaystyle \binom{6}{4}\cdot 4!=\dfrac{6!}{4!2!}\cdot 4! = \dfrac{6!}{2!}=6\times 5\times 4 \times 3=360[/tex]

Since each game lasts half a hour, it would take 180 hours to play all the possible games

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