Answer :
Answer:
There are 136 different ways for the instructor to select 2 textbooks from a possible 17 textbooks.
Step-by-step explanation:
There are 17 textbooks.
To choose 2 textbooks from possible 17 textbooks an instructor has
[tex]C^{17}_2[/tex]
different ways.
Count [tex]C^{17}_2:[/tex]
[tex]C^{17}_2=\dfrac{17!}{2!\cdot (17-2)!}=\dfrac{17!}{2!\cdot 15!}=\dfrac{15!\cdot 16\cdot 17}{2\cdot 15!}=\dfrac{16\cdot 17}{2}=8\cdot 17=136[/tex]
Hence, there are 136 different ways for the instructor to select 2 textbooks from a possible 17 textbooks.
The number of ways can an instructor select 2 textbooks from a possible 17 is 136.
What is a combination?
Combinations are the way of selecting objects or elements from a group of objects or collections, in such a way the order of the objects does not matter.
We know that the formula is given as
[tex]\rm ^nC_r[/tex]
where n is the total sample and r is the selected sample from the total sample.
Then the number of ways can an instructor select 2 textbooks from a possible 17 will be
[tex]\rm ^{17}C_2 = \dfrac{17!}{15!*2!} = \dfrac{17*16}{2} = 136[/tex]
Thus, the number of ways can an instructor select 2 textbooks from a possible 17 is 136.
More about the combination link is given below.
https://brainly.com/question/25351212