The final speed of the elevator is 14.0 m/s
Explanation:
The motion of the elevator is a uniformly accelerated motion, so we can use the suvat equation:
[tex]v=u+at[/tex]
where
v is the final speed
u is the initial speed
a is the acceleration
t is the time
In this problem,
u = 0 (the initial speed (the elevator starts from rest)
[tex]a=3.5 m/s^2[/tex] is the acceleration of the elevator
t = 4.0 s is the time
Substituting, we find the final speed:
[tex]v=0+(3.5)(4.0)=14.0 m/s[/tex]
Learn more about accelerated motion:
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