Answer :
Answer:
HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)
Explanation:
An ionic equation uses the symbols (aq) [aqueous] to indicate molecules and ions that are soluble in water, (s) [solid] to indicate insoluble solids, and (ℓ) to indicate substances (usually water) in the liquid state.
In this reaction, aqueous sodium hydroxide reacts with aqueous formic acid to form sodium formate and water.
1. Molecular equation
HCHO₂(aq) + NaOH(aq) ⟶ NaCHO₂(aq) + H₂O(ℓ)
2. Ionic equation
Sodium hydroxide and sodium formate are soluble ionic compounds, so we write them as hydrated ions.
HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)
The complete ionic equation will be:
[tex]H^+(aq)+CHO_2^-(aq)+Na^{+}(aq)+OH^-(aq)\rightarrow Na^+(aq)+CHO_2^-(aq)+H_2O(l)[/tex]
Given:
The chemical reaction between formic acid and sodium chloride.
[tex]HCHO_2(aq)+NaOH(aq)\rightarrow NaCHO_2(aq)+H_2O(l)[/tex]
To find:
The complete ionic equation of the given chemical reaction.
Solution:
[tex]HCHO_2(aq)+NaOH(aq)\rightarrow NaCHO_2(aq)+H_2O(l)[/tex]
The formic acid dissociates into a hydrogen ion and formate ion in its aqueous phase.
[tex]HCHO_2(aq)\rightarrow H^+(aq)+CHO_2^-(aq)[/tex]
The sodium hydroxide dissociates into a sodium ion and hydroxide ion in its aqueous phase.
[tex]NaOH(aq)\rightarrow Na^{+}(aq)+OH^-(aq)[/tex]
The sodium formate dissociates into a sodium ion and formate ion in its aqueous phase.
[tex]NaCHO_2(aq)\rightarrow Na^+(aq)+CHO_2^-(aq)[/tex]
Replace the aqueous compounds with their ionic equations to have the complete ionic equation of the reaction.
So, the complete ionic equation will be:
[tex]H^+(aq)+CHO_2^-(aq)+Na^{+}(aq)+OH^-(aq)\rightarrow Na^+(aq)+CHO_2^-(aq)+H_2O(l)[/tex]
Learn more about the complete ionic equation here;
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