Andy​, Beth​, and Cindy each went for a walk yesterday afternoon. Andy walked 2 and three fourths mi at a constant speed of 2 and one half mi divided by h . Beth walked 1 and one half mi at a constant speed of 1 and one eighth mi divided by h . Cindy walked for 1 h and 24 min at a constant speed of 1 and one fourth mi divided by h . List the three people in order of the times they spent walking from least time to greatest time. Choose the correct answer below. A. Beth​, Cindy​, Andy B. Cindy​, Andy​, Beth

Answer :

Answer:

The correct order from least time to greatest time is: Andy, Beth, Cindy.

Step-by-step explanation:

Consider the provided information,

Andy walked [tex]2\frac{3}{4}[/tex] mi at a constant speed of [tex]2 \frac{1}{2}[/tex] mi/h.

As we know: [tex]Time= \frac{Distance}{Speed}[/tex]

[tex]Time= \frac{2\frac{3}{4}}{2 \frac{1}{2}}[/tex]

[tex]Time= \frac{\frac{11}{4}}{\frac{5}{2}}[/tex]

[tex]Time= \frac{11}{10}[/tex]

Therefore, Andy takes 1.1 hours.

Beth walked [tex]1\frac{1}{2}[/tex] mi at a constant speed of [tex]1\frac{1}{8}[/tex] mi/h .

[tex]Time= \frac{1\frac{1}{2}}{1 \frac{1}{8}}[/tex]

[tex]Time= \frac{\frac{3}{2}}{\frac{9}{8}}[/tex]

[tex]Time= \frac{4}{3}[/tex]

Therefore, Beth takes 1.33 hours.

Cindy walked for 1 h and 24 min at a constant speed of [tex]1\frac{1}{4}[/tex] mi/h.

[tex]1\: hour \: 24 \: minutes \: = 1+ \frac{24}{60}hours = 1.4\ hours[/tex]

Therefore Cindy takes 1.4 hours.

Andy spent least time i.e 1.1 hours and Cindy spent greatest time i.e 1.4 hours.

The correct order from least time to greatest time is: Andy, Beth, Cindy

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