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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is the approximate percent error?

Answer :

Hagrid
Using the accepted density of CO2 at STP, we get the expected volume of the gas.
0.10 g / (1.96g/L) = 0.051 g

Calculating for the percent error:
%error =( |0.051 - 0.056| / 0.051 ) (100) = 9.80%

The percent error is 9.80%.

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