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Two blocks are placed at the ends of a horizontal massless board, as in the drawing. The board is kept from rotating and rests on a support that serves as an axis of rotation. The block on the right has a mass of 2.8 kg. Determine the magnitude of the angular acceleration when the system is allowed to rotate.

Answer :

Answer:

The magnitude of the angular acceleration ∝ = [tex]\frac{rxF}{2.8[tex]r^{2}[/tex]}[/tex]

Explanation:

The angular acceleration ∝ is equal to the torque (radius multiplied by force) divided by the mass times the square of the radius. The magnitude of angular acceleration ∝ will have the equation above but we have to replace the mass in the equation by 2.8kg as stated.

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