Explanation:
Whenever we want to discuss the motion of a body,we need to consider the forces acting on that body and not the force it is exerting on other bodies.
Let [tex]F[/tex] be the force exerted by the other player on you.
Horizontal force exerted by other player is [tex]FCos(\alpha )[/tex] where [tex]\alpha[/tex] is the angle between the direction of force and horizontal.
Given,
[tex]F=1200N\\\alpha =20^{0}[/tex]
So,the horizontal force is [tex]F_{h}=1200\times Cos20=1127.63N[/tex]
Vertical force exerted is [tex]F_{v}=1200\times Sin(20)=410.42N[/tex]
Normal reaction force from ground is the sum of vertical force and my weight=[tex]N=80(9.8)+410.42=1194.42N[/tex]
Let the coefficient of static friction be [tex]c_{s}[/tex]
given,[tex]c_{s}=0.95[/tex]
Maximum frictional force is [tex]f=N\times c_{s}=1194.42\times 0.95=1134.7N[/tex]
Since the maximum frictional force is greater than the horizontal force,I will not accelerate backwards.