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At the SuperSpeedy drive-through the time between consecutive customer arrivals has a mean of 50 seconds and a standard deviation of 30 seconds. There are two servers whose service time averages 80 seconds with a standard deviation of 20 seconds. Assume that no customers leave the drive-through after entry. a. What is the utilization of the employees?

Answer :

Answer:

utilization of employee is 80%

Step-by-step explanation:

Given data:

mean = 50 sec

standard deviation is 30 sec

Average number of arrivals/ sec is

[tex]\lambda = \frac{1}{50}[/tex]

service rate id 80 sec

[tex]\mu =\frac{1}{80}[/tex]

The utilzation of employee is calculated as

[tex]\frac{\lambda}{c\mu} = \frac{80}{2\times 50} = 0.8[/tex]

i.e 80%

utilization of employee is 80%

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