Answered

What is the completely factored form of p4 - 16?
(0-2)(0 - 2)(0 + 2)(0+2)
(0-2)(0-2)(P-2)(0-2)
(0-2) (0+2)(x² + 20+4)
(0-2) (0+2) (0²+4)

Answer :

absor201

The completely factored form of p^4-16 is:

[tex](p^2+4)(p+2)(p-2)[/tex]

Step-by-step explanation:

We have to factorize the given expression to get the final result

Given

[tex]p^4-16\\Using\ Formula: a^2-b^2=(a+b)(a-b)\\(p^2)^2-(4)^2\\=(p^2+4)(p^2-4)[/tex]

p^2-4 can further be factored again

[tex]=(p^2+4)[(p)^2-(2)^2]\\=(p^2+4)(p+2)(p-2)[/tex]

The completely factored form of p^4-16 is:

[tex](p^2+4)(p+2)(p-2)[/tex]

Keywords: Factorization

Learn more about factorization at:

  • brainly.com/question/9323337
  • brainly.com/question/9381080

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