Answer :
Answer:
F'= 10F (N)
Explanation:
To solve this problem we apply Coulomb's law:
Two point charges (q₁, q₂) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:
F = K*q₁*q₂ / d² Formula (1)
F: Electric force in Newtons (N)
K : Coulomb constant in N*m²/C²
q₁,q₂:Charges in Coulombs (C)
d: distance between the charges in meters(m)
Calculating of the new force F'
Data:
q'₁ = 5q₁
q'₂ = q₂/2
d' = d/2
We apply the Coulomb's law:
F' = K*q'₁*q'₂ / d'²
F'= K*(5q₁)*(q₂/2) / (d/2)²
F'= K*(5q₁*q₂/2) / (d²/4)
F'= K*20q₁*q₂) / (2d²)
F'= 10(K*q₁*q₂) / (d²)
F'= 10(K*q₁*q₂) / (d²) , F = K*q₁*q₂ / d²
F'= 10F (N)