Answer :
Answer:
[tex]\Delta t = 0.1s[/tex]
Explanation:
We need to calculate the difference between the times the waves from the bass sounds ([tex]t_b[/tex]) and treble sounds ([tex]t_t[/tex]) take to reach us, that is, [tex]\Delta t = t_b-t_t[/tex].
Since [tex]v=\frac{d}{t}[/tex], then [tex]t=\frac{d}{v}[/tex] and we can write:
[tex]\Delta t = t_b-t_t=\frac{d}{v_b} - \frac{d}{v_t}=d(\frac{1}{v_b} - \frac{1}{v_t})=(120m)(\frac{1}{300m/s} - \frac{1}{400m/s})=0.1s[/tex]