Answer:
Circle Q is 2 units to the right of circle P and 10 units above it.
Circle Q has a longer radius than circle P.
Step-by-step explanation:
The equation for the circle P is [tex](x+4)^2 + (y+7)^2 = 16[/tex]
Its center is in (-4,-7) and the radius is [tex]r=\sqrt{16} =4[/tex]
The equation for the circle Q is [tex](x+2)^2 + (y-3)^2 =25[/tex]
Its center is in (-2,3) and the radius is [tex]r=\sqrt{25} =5[/tex]
Subtracting (-2,3)-(-4,-7)=(2,10)
The center of Q is 2 units to the right of the center of P and is 10 units above.
The radius of Q is longer than the radius of P
